Question

please answer this question.... THE BEST ANSWER will surely be marked as BRAINLIEST. PLEASE DON'T send Anything but tha ANSWER. ​

Answer 1

Here we have,

$\frac{x^2 - (x + 2)(x + 3)}{7x + 1} = \frac{2}{3}$

Now first lets have a look at the LHS.

We have.

$\frac{x^2 - (x+2)(x+3)}{7x + 1}$

On the numerator,

We can use the identity of (x + a)(x + b) = x² + (a + b)x + ab.

So, x = x. a = 2. b = 3.

So we have,

(x + 2)(x + 3) = x² + (2 + 3)x + (2)(3)

= x² + 5x + 6.

Now put this value to get,

$\frac{x^2 - (x^2+ 5x+6)}{7x+1}$

$\frac{x^{2} -x^2-5x-6}{7x + 1}\\ = \frac{-5x - 6}{7x+1}$

Now lets equate.

So we have,

$\frac{-5x - 6}{7x +1} = \frac{2}{3} \\\\= 3(-5x-6) = 2(7x+1)\\\\= -15x - 18= 14x +2\\\\= -18 - 2=14x + 15x\\-20 = 29x\\\\= x = \frac{-20}{29}$

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