Math, asked by hero65, 1 year ago

please answer this question tomorrow is my paper

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Answered by skh2
0
Hello,

Very good and tricky question.

The formulae that will be used in the question are

 {x}^{a} \times {x}^{b} = {x}^{a + b} \\ {x}^{a} \div {x}^{b} = {x}^{a - b} \\
Now, using the second one we simplify the above question as follows.

[tex] {( \frac{ {x}^{b} }{ {x}^{c} }) }^{(b + c )- a} \times {( \frac{ {x}^{c} }{ {x}^{a} }) }^{(c + a)- b} \times {( \frac{ {x}^{a} }{ {x}^{b} }) }^{(a + b) - c} \\ {( {x}^{(b - c)} )}^{(b + c )- a)} \times {( {x}^{(c - a)} )}^{(c + a )- b)} \times {( {x}^{(a - b)} )}^{(a + b )- c)} \\ \\ using \: \: { {(x}^{m} )}^{n} = {x}^{mn } \\
X^b²-c²-ab+ac +c²-a²-bc+ab+a²-b²-ac+bc
X^0 =1


Hope this will be helping you ✌️
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