please answer this question. Urgent
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EXPLANATION:-
For numerator We expanded by formula of
(a-b)³ = a³-b³ -3ab(a-b)
After expansion ,
We can simplify the numerator
After simplification of numerator
Take common 3
After we can get a equation
We can simplify by the formula of
a²-b² = (a+b)(a-b)
We can get a equation
According to that equation We have to simplify By using According to the Question data
a² + b² + c² = 0 => Given So,
- a² + b² = -c²
- a² + c² = -b²
- b² + c² = -a²
Substitute these values in numerator and take a common -a²b²c² After taking this The entire numerator gets converted interms of denominator .So , both cancelled each other . -a²b²c² Remains in the numerator
So, the answer is -a²b²c² [b]
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