if alpha and beta are the zeros of the polynomial 29x square+13x+3=0find the value of alpha square +beta square
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Answer:
let p(x)=29x^2+13x+3
since à. and ß are the zeroes given polynomial P(X)
so, à+ß=-b/a = -13/29
and àß ==c/a=3/29
now, à^2+ß^2=(à+ß)²-à.ß
=(-13/29)²-3/29
=169/841-3/29
=169-87/841
=82/841
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