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HI DEAR,
1ST TERM =( 2√6)/(√2+√3) ×(√2-√3)/(√2-√3) = 6√2-4√3
2ND TERM =( 6√2)/(√6+√3)×(√6-√3)/(√6-√3) = 4√3-2√6
3RD TERM = (8√3)/(√6+√2)×(√6-√2)/(√6-√2) = 6√2-2√6
NOW, 6√2-4√3+4√3-2√6-6√2+2√6
= 0
HOPE IT HELPS...
MARK BRAINLIEST..❤❤
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