Question

Please answer this question with explanationA 8000 kg engine pulls a train of 5 wagons,,each of 2000 kg along a horizontal track .If the engine exerts a force of 40000 N and track offers a friction force of 5000 N, then calculate<

(a) the net acceleration force
(b) the acceleration of train and
(c) the force of wagon 1 on wagon 2

Answer 1

Answer:

HEY .....HERE IS YOUR ANSWER..⇒

(a) Force exerted by the engine, F = 40000 N

Frictional force offered by the track, Ff = 5000 N

Net accelerating force, Fa = F Ff = 40000 5000 = 35000 N

Hence, the net accelerating force is 35000 N.

(b) Acceleration of the train = a

The engine exerts a force of 40000 N on all the five wagons.

Net accelerating force on the wagons, Fa = 35000 N

Mass of the wagons, m = Mass of a wagon x Number of wagons

Mass of a wagon = 2000 kg

Number of wagons = 5

m = 2000 — 5 = 10000 kg

Total mass, M = m = 10000 kg

From Newton’s second law of motion:

Fa= Ma

a=Fam = 35000 10000 = 3.5 ms^(-2)

Hence, the acceleration of the wagons and the train is 3.5 m/s2.

(c) Mass of all the wagons except wagon 1 is 4 — 2000 = 8000 kg

Acceleration of the wagons = 3.5 m/s2

Thus, force exerted on all the wagons except wagon 1

= 8000 — 3.5 = 28000 N

Therefore, the force exerted by wagon 1 on the remaining four wagons is 28000 N.

Hence, the force exerted by wagon 1 on wagon 2 is 28000 N.