Question

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Answer 1

Answer

Charge , Q = 80μ C

Option 3 is correct

Given

Everything is in attachment

To Find

Charge on the 4μF condenser

Formula

$\bf \bigstar \;\; Q=CV$

Solution

4μF and 8μF are connected in Parallel. So ,

⇒ Cp = 4μF + 8μF

⇒ Cp = 12μF

Now 4μF and 8μF are connected in series with 12μF .So,

Ceq = 12 × 12 / 2(12)

⇒ Ceq = 6μF

Eq. Capacitance = 6uF

⇒ Ceq = Q/V

⇒ Q = 6×20 = 120uC

Charge remains same on each capacitor in series.

Charge on 12uF = 120uC

Charge on parallel connection (4uF & 8uF) = 120uC

Voltage remains same across each capacitor in parallel.

⇒ V₁ = V₂

⇒ Q₁/C₁ = Q₂/C₂

⇒ C₁/C₂ = Q₁/Q₂

⇒ 4uF/8uF = Q₁/Q²₂

⇒ Q₁ : Q₂ = 1 : 2

So, charge on 4uF = 40uC

So , charge on the plate of 4μF condenser is 80μ C

Answer 2

• Given -

• Capacity of condenser is 4uc
• Voltage charged on condenser is 20 volts

• To Find -

• Charge on plate of condenser of 4uc condenser

• Solution -

We know Formula for charge is,

$\boxed{★ Q = CV}$

Here,

• Q = charge
• C = capacity
• V = voltage

Applying Values according to given conditions,

$⟹Q = 4 \times 20$

$⟹Q = 80$

⛬ Charge in the 4uc condenser is 20Uc. Hence, option (3) is correct.