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Perimeter of rectangle = 20 cm
⇒2( l+b) = 20 cm
⇒ l+b = 10 cm
⇒ l = (10-b) cm
Now,
Area of rectangle = 21 cm²
⇒ l×b = 21 cm²
⇒(10-b)×b = 21 cm²
⇒ b² - 10b +21 = 0
∴ b = 7 cm OR b = 3 cm
then, l = 3cm OR l = 7 cm
Now,
The side of the square= a = 7cm - 3 cm
= 4 cm
∴ Perimeter of the square = 4a
= 4 × 4cm
= 16 cm
The perimeter of the square formed in middle is 16 cm (Option B)
I hope this helps you ^_^
⇒2( l+b) = 20 cm
⇒ l+b = 10 cm
⇒ l = (10-b) cm
Now,
Area of rectangle = 21 cm²
⇒ l×b = 21 cm²
⇒(10-b)×b = 21 cm²
⇒ b² - 10b +21 = 0
∴ b = 7 cm OR b = 3 cm
then, l = 3cm OR l = 7 cm
Now,
The side of the square= a = 7cm - 3 cm
= 4 cm
∴ Perimeter of the square = 4a
= 4 × 4cm
= 16 cm
The perimeter of the square formed in middle is 16 cm (Option B)
I hope this helps you ^_^
HappiestWriter012:
Great!
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