Question

please answer this question.

wrong answers will be reported​

Answer 1

Answer:

In ΔQTR, ∠TRS is an exterior angle.

∠QTR + ∠TQR = ∠TRS.

∠QTR = ∠TRS − ∠TQR......(1)

For ΔPQR, ∠PRS is an external angle.

∠QPR + ∠PQR = ∠PRS

∠QPR + 2∠TQR = 2∠TRS

(As QT and RT are angle bisectors)

∠QPR = 2(∠TRS − ∠TQR) ∠QPR = 2∠QTR

[By using equation (1)]

∠QTR = 1/2 ∠QPR

Hence proved

Hope it helps!