Question

find the zeros of the polynomial :r(x) =(x-2)^2+(x+2)^2​

Answer 1

Step-by-step explanation:

Let the polynomial g(x) be (x-2)² + (x+2)²

now equate g(x) to 0,

which implies, (x-2)² + (x+2)² = 0

x² -2² + x² +2² = 0

(x²+x²) + ( 2²-2²) = 0

2x² + 0 = 0

2x² = 0

x² = 0/2

x² = 0

x = √0

x = 0

therefore, 0 is the zero of the polynomial g(x)= (x-2)² + (x+2)²

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