PLEASE ANSWER THIS QUESTIONS
BRAINLIEST QUESTION
If a man increases his speed by 25%, he would take 10 minutes less to reach his destination. If he increases his speed by 100/9%, find the number of minutes he saves to reach his destination.
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Answers
And the original speed be b m/s
Time taken = a / b
New speed = b + 25 % of b = b + b/4 = 5b/4
Time taken when speed is increased by 25% = [ a / (5b/4)] = 4a/5b
____________________________
When speed is increased by 100/9 %
Speed = b + 100/9 % of b
= b + ( 100 / 9) b/ 100
= b + b/9
= 10b / 9
Time taken when speed is increased by 100/9 % = [ a / (10b /9)] = 9a/10b
___________________________
According to question,
a/b - 4a/5b = 10 /60
=> a / 5b = 1/6
=> a/b = 5 /6 -----(1)
Time saved to reach the destination when speed is increased by 100/9 % = a/b - 9a/10b hours
= ( 10a - 9a) / 10b hours
= a/b × 1/10 hours
= 5/6 × 1/10 hours
= 1 / 12 hours
= 1 × 60 / 12 minutes
= 5 minutes
☃️ required answer ::-
Let the distance between starting position to the final position be a m
And the original speed be b m/s
Time taken = a / b
New speed = b + 25 % of b = b + b/4 = 5b/4
Time taken when speed is increased by 25% = [ a / (5b/4)] = 4a/5b
____________________________
When speed is increased by 100/9 %
Speed = b + 100/9 % of b
= b + ( 100 / 9) b/ 100
= b + b/9
= 10b / 9
Time taken when speed is increased by 100/9 % = [ a / (10b /9)] = 9a/10b
___________________________
According to question,
a/b - 4a/5b = 10 /60
=> a / 5b = 1/6
=> a/b = 5 /6 -----(1)
Time saved to reach the destination when speed is increased by 100/9 % = a/b - 9a/10b hours
= ( 10a - 9a) / 10b hours
= a/b × 1/10 hours
= 5/6 × 1/10 hours
= 1 / 12 hours
= 1 × 60 / 12 minutes
= 5 minutes