Question

please answer this step by step .​

Answer 1

Step-by-step explanation:

SEE THE ATTACHMENT.......

Answer 2

Answer:

x^-2 =64

$\frac{1}{ {x}^{2} } = 64$

${ (\frac{1}{x} )}^{2} = 64$

$\frac{1}{x} = 8$

$x = \frac{1}{8}$

${x}^{ \frac{1}{3} } + {x}^{0} = { (\frac{1}{8} )}^{ \frac{1}{3} } + { \frac{1}{8} }^{0}$

Any Number to the power 0 = 1

$= \sqrt[3]{ \frac{1}{8} } + 1$

$\frac{1}{2} + 1$

$\frac{3}{2}$

So answer is 3/2