Math, asked by Ridajenan12, 3 months ago

Please answer this.. Urgent

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Answered by StormEyes
1

\sf \Large Solution!!

\sf \to \dfrac{2}{3}+\dfrac{4}{5}÷\dfrac{2}{5}-3

\sf \to \dfrac{2}{3}+\dfrac{\cancel{4}^{2}}{\cancel{5}}\times \dfrac{\cancel{5}}{\cancel{2}}-3

\sf \to \dfrac{2}{3}+2-3

\sf \to \dfrac{2+6-9}{3}

\sf \to \dfrac{-1}{3}

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