Question

please answer thise
n/3+1=4-n
​

Answer 1

$\frac{n}{3} + 1 = 4 - n \\ \frac{n + 3}{3} = 4 - n \\ n + 3 = 3(4 - n) \\ n + 3 = 12 - 3n \\ n + 3n = 9 \\ 4n = 9 \\ n = 9 \div 4$

$\small\bold\green{hope \: it \: helps}$

Answer 2

Answer:

\begin{gathered}\frac{n}{3} + 1 = 4 - n \\ \frac{n + 3}{3} = 4 - n \\ n + 3 = 3(4 - n) \\ n + 3 = 12 - 3n \\ n + 3n = 9 \\ 4n = 9 \\ n = 9 \div 4\end{gathered}

3

n

+1=4−n

3

n+3

=4−n

n+3=3(4−n)

n+3=12−3n

n+3n=9

4n=9

n=9÷4

\small\bold\green{hope \: it \: helps}hopeithelps