Please answer to the following.
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2
Answer:
0
Step-by-step explanation:
If we take i^n common then
i^n(1+i+i^2+i^3)
=i^n{1+i+(-1)+(-i) }
=i^n(0)
=0
Answered by
5
If we take iⁿ common then
iⁿ(1+i+i²+i³)
= iⁿ{1+i+(-1)+(-i) }
= iⁿ(0)
= 0
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