Math, asked by honey3303, 3 months ago

please answer to this ​

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Answered by Anonymous
22

\Large{\textsf{\textbf{ Question :-}}}

if \large\rm{ A = \left[ \begin{array}{cc} 1 & 0 \\ 0 & 1 \end{array} \right] }

and

\large\rm{ B =  \left[ \begin{array}{cc} 2 & 3 \\ 4 & 5 \end{array} \right] }

then find

\large\rm AB

\Large{\textsf{\textbf{ Answer :-}}}

Given that,

\large\rm{ A = \left[ \begin{array}{cc} 1 & 0 \\ 0 & 1 \end{array} \right] } and \large\rm{ B =  \left[ \begin{array}{cc} 2 & 3 \\ 4 & 5 \end{array} \right] }

\large\rm

\scriptsize\rm{  = \left[ \begin{array}{cc} \rm a & \rm b \\ \rm c & \rm d \end{array} \right] \times  \left[ \begin{array}{cc} \rm e & \rm f \\ \rm g & \rm h \end{array} \right] =  \left[ \begin{array}{cc} \rm a \ast e + c \ast g & \rm a \ast f +  c \ast h \\ \rm b \ast e + b \ast g & \rm b \ast f + d \ast h \end{array} \right] }

\large\rm

\large\rm{ = \left[ \begin{array}{cc} 1 \times 2 + 0 \times 4 & 1 \times 3 + 0 \times 4 \\ 0 \times 2 + 0 \times 4 & 0 \times 3 + 1 \times 5 \end{array} \right] }

\large\rm

\large\rm{ = \left[ \begin{array}{cc} 2+0 & 3+0 \\ 0+0 & 3+5 \end{array} \right]}

\large\rm

\large\rm{ = \left[ \begin{array}{cc} 2 & 3 \\ 0 & 5 \end{array} \right]}

\large\rm

\large\rm{ \:\:\:\:\:\;\:\:\;\:\:\: = (2)(5) - (3)(0)}

\large\rm

\large\rm{ \:\:\:\:\:\;\:\:\;\:\:\: = 10 - 0}

\large\rm

\large\rm{ \:\:\:\:\:\;\:\:\;\:\:\: = 10}


ZzyetozWolFF: Well explained! :) ❤
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