Question

Please answer to this question

Answer 1

Solution:-

Given

$\sf \to \: \dfrac{y - 4}{y + 2} = \dfrac{1}{4}$

To find the value of Y

Now Take

$\sf \to \: \dfrac{y - 4}{y + 2} = \dfrac{1}{4}$

Using cross multiplication methods

$\sf \to \: 4(y - 4) = 1(y + 2)$

$\sf \to \: 4y - 16 = y + 2$

$\sf \to \: 4y - y = 2 + 16$

$\sf \to \: 3y = 18$

$\sf \to \: y = \dfrac{18}{3} = 6$

So y = 6

Now check our answer

$\sf \to \: \dfrac{y - 4}{y + 2} = \dfrac{1}{4}$

$\sf \to \: \dfrac{6 - 4}{6 + 2} = \dfrac{1}{4}$

$\sf \to \: \dfrac{2}{8} = \dfrac{1}{4}$

$\sf \to \: \dfrac{1}{4} = \dfrac{1}{4}$

LHS = RHS

Answer 2

Question :-

If $\sf \frac{y - 4}{y + 2} = \frac{1}{4}$ then value of y is

Answer :-

$\implies\sf \frac{y - 4}{y + 2} = \frac{1}{4} \\ \\ \implies\sf4(y - 4) = (y + 2) \\ \\ \implies\sf4y - 16 = y + 2 \\ \\ \implies\sf4y - y = 16 + 2 \\ \\ \implies\sf 3y = 18 \\ \\ \implies\sf y = \frac{18}{3} \\ \\\implies\sf y = 6$