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Area cleaned = A. of Δ.ABC + A. of ΔACD\
∴A. ofΔABC = 1/2 * 40 * 9
180m²
By pythagoreas theorem, 9² +40² =AC²
81 + 1600 = AC²
√1681 = AC
AC = 41 m
A. of ΔACD = (Find using herons formula )
Then , after finding ΔACDs area,
Add both the triangles area
You will get the answer
Hope this will help u
∴A. ofΔABC = 1/2 * 40 * 9
180m²
By pythagoreas theorem, 9² +40² =AC²
81 + 1600 = AC²
√1681 = AC
AC = 41 m
A. of ΔACD = (Find using herons formula )
Then , after finding ΔACDs area,
Add both the triangles area
You will get the answer
Hope this will help u
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