Question

please answer urgent

$25 {x}^{2} + 25x + 5 \\ \\ find \: sum \: of \: zeroes \: and \: product \: of \: zeroes \\ \\ and \: also \: find \frac{1}{ { \alpha \: }^{2} } \: + \frac{1}{ { \beta }^{2} } \: \: + 1$
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Answer 1

Step-by-step explanation:

sum of the zeros =-25/25=-1

product of the zeros =5/25=1/5

(-1*-1-2+1)/125=3/125

Answer 2

HEY MATE!! HERE IS YOUR ANSWER

GIVEN

$25 {x}^{2} + 25x + 5 \\ a \: and \: \beta \ \: the \: \: zeros \: of \: the \: \\ polynomial$

$\alpha + \beta = - b/a = - 25/25 = -1$

$\alpha \beta = c/a = 5/25= 1/5$

$( \alpha + \beta ) {}^{2} = ( - 1) {}^{2} \\ { \alpha }^{2} + 2 \alpha \beta + { \beta }^{2} + 2 \binom{1}{5} = 1$

A2 + B2 = 1-2/5 = 3/5

1/A2 + 1/B2 = (A2+B2)/(a2b2)= A2+b2/ab2

3/5÷(1/5)°2

3/5÷1/25 = 3/5×25=15

HOPE IT HELPS ☺️

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