Question

PLEASE ANSWER URGENTLY.


1m^3 of ice weighs 900 kg. What is the weight of a cubical block of ice of side 0.5 m?

Answer 1

Answer:

Step-by-step explanation:

Weight of 1 m3 of cube = 900 kg Volume of 0.5 m of length = (0.5)3 m3 ⇒Weigh of 0.5 m of length = (0.5)3 × 900 kg ⇒Weigh of 0.5 m of length = 112.5 kg

Answer 2

Weight of 1 m^3 of ice = 900 kg

Length of edge of cubical block of ice = 0.5 m

We know that volume of cube is the result we get after we raise the length of edge of cube to three so,

Volume of cubical block of ice = ( Edge of cubical block ) ^ 3
V = ( 0.5 ) ^ 3
V = 0.125 m ^ 3
Volume of cubical block of ice = 0.125 m ^ 3

Since,

1 m^3 of ice weighs 900 kg.

Therefore,

0.125 m ^ 3 of ice will weigh ( 900 * 0.125 ) kg

0.125 m ^ 3 of ice will weigh ( 9 * 1.25 ) kg

0.125 m ^ 3 of ice will weigh 11.25 kg.

Hence,

Weight of cubical block of ice = 11.25 kg