Question

please answer urgently​

Answer 1

Given :

• R 1 = 7.2 Ω
• R 2 = 8 Ω
• R 3 = 12 Ω

To find :

• Equivalent resistance

Solution : -

R 2 and R 3 are connected in parallel with each other

Equivalent resistance for n number of resistors connected in parallel is given by ,

➜ 1 / Rp = 1 / R 1 + 1 / R 2 ....+ 1 / R n

Hence ,

➜ 1 / R p = 1 / R 2 + 1 / R 3

➜ 1 / R p = 1 / 8 + 1 / 12

➜ 1 / Rp = 3 + 2 /24

➜ 1 / R p = 5 / 24

➜ Rp = 4.8 Ω

Now , Rp and R 1 are in series with each other

Equivalent resistance for n number of resistors connected in series is given by ,

➜  Rs = R 1 = R 2 ...+ R n

Hence ,

➜  R s = Rp + R 1

➜  R s = 4.8 + 7.2

➜  Rs  = 12 Ω

The equivalent resistance of the circuit is 12 Ω