Question

The normal form of equation of the line
x– √3 y = 10 is​

Answer 1

The normal form of equation of the line

x– √3 y = 10 is x-√3y-10=0

Answer 2

Given :  x– √3 y = 10

To Find :  The normal form of equation of the line

Solution:

x cos α + y sin α = p is   normal form of equation of the line

x – √3 y = 10

Dividing both sides by 2

=> x/2  - √3 y/2 = 10/2

=> (1/2)x  - (√3 /2)y = 5

cos(-π/3) = 1/2

Sin(-π/3) =  - (√3 /2)

Hence

xcos(-π/3) + ysin(-π/3) = 5

or

xcos(5π/3) + ysin(5π/3) = 5

Learn More:

y-3=2(x+1) complete the missing value in the solution to the equation

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