Question

please answer using steps and explain properly... ☺

Answer 1

let the triangle be /\ ABC
(angle)ABC =90° ----(say)
thus;height = 24 cm
base = 24 cm
since; (area of triangle)=(half)×(base)×(height)
area = {24 × 24} ÷ 2
area = 288

AREA OF REQUIRED TRIANGLE IS 288 sq. cm

Answer 2

Let the other side be x

${40}^{2} = {24 }^{2} + {x}^{2}$
$1600 = 576 + {x }^{2}$
$1600 - 576 = {x}^{2}$
$1024 = {x}^{2}$
$x = \sqrt{1024}$
$x = 32$
Area of right angled triangle =
$\frac{1}{2} \times base \times height$
$\frac{1}{2} \times 24 \times 32$
$384 \: {cm}^{2}$
Please mark me brainliest.........