Question

Please answer.. very urgent

Answer 1

$Given: 4^{2x - 1} - 16^{x- 1} = 384$

$4^{2x - 1} - (4^2)^{x - 1} = 384$

$4^{2x - 1} - 4^{2x - 2} = 384$

$4^{2x} ( 4^{-1} - 4^{-2} ) = 384$

$4^{2x} = \frac{384}{ 4^{-1} - 4^{-2} }$

$4^{2x} = \frac{384}{ \frac{1}{4} - \frac{1}{16} }$

$4^{2x} = \frac{384}{ \frac{3}{16} }$

$4^{2x} = 2048$

$(2^2)^{2x} = 2048$

$2^{2 * 2x} = 2^{11}$

2 * 2x = 11

4x = 11

x = 11/4.

x = 2.75.


Hope this helps!

Answer 2

Hi,

Please see the attached file!


Thanks