Chemistry, asked by jyotirmaykrjha, 1 year ago

Please answer with a solution.

67.2 l of H2 combined with 44.8 l of N2 to form Ammonia.

N2 + 3 H2 ----> 2 NH3

What is the other substance that remains in the mixture ?

Answers

Answered by rohityadav1829
0
67.2 l of H2 combined with 44.8 l of N2 to form Ammonia. N2 + 3 H2 ----> 2 NH3 What is the other substance that remains in the mixture ? Ask for details; Follow ...
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