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number of moles of Mg= mass of Mg/molar mass of Mg
= 12g/24g = 0.5 moles
1 mol of Mg reacts with 1 mol of H2SO4 to give 1 mol of MgSO4 and 1 mol of hydrogen.
(Ratio- 1:1:1:1)
Therefore 0.5 mol of Mg will react with 0.5 mol of H2SO4 to give 0.5 mol of MgSO4 and 0.5 mol of hydrogen.
Mass of MgSO4 formed = number of moles of MgSO4 x molar mass of MgSO4
= 0.5 x 120 = 60g
60g of MgSO4 will be formed.
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= 12g/24g = 0.5 moles
1 mol of Mg reacts with 1 mol of H2SO4 to give 1 mol of MgSO4 and 1 mol of hydrogen.
(Ratio- 1:1:1:1)
Therefore 0.5 mol of Mg will react with 0.5 mol of H2SO4 to give 0.5 mol of MgSO4 and 0.5 mol of hydrogen.
Mass of MgSO4 formed = number of moles of MgSO4 x molar mass of MgSO4
= 0.5 x 120 = 60g
60g of MgSO4 will be formed.
Hope this helped. Pls mark me as the brainliest
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