Please answer with proper steps of 3 and 4 question. It is about surface and lateral surface area. Please explain and help.
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Area of four Walls of room =2(l+b)h
=2(12+8)4=160m^2
area of ceiling =12×8=96m^2
total area of room =160+96=256m^2
total cost of white washing the room =256×5=rs1280
[Lateral surface area = area of four Walls =2{l+b}×h]
=2(12+8)4=160m^2
area of ceiling =12×8=96m^2
total area of room =160+96=256m^2
total cost of white washing the room =256×5=rs1280
[Lateral surface area = area of four Walls =2{l+b}×h]
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