the acceleration (a) of moving particle varies with position according to the following relation a=x^2+3x. then correct relation between velocity and displacement is
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Hi
when we integrate the acceleration then we get velocity
here a=x^2+3x
now integrate we get
v=x^3/3+3x^2/2
take lcm
we get
6v=2x^3+9x^2
hope u got ur answer
when we integrate the acceleration then we get velocity
here a=x^2+3x
now integrate we get
v=x^3/3+3x^2/2
take lcm
we get
6v=2x^3+9x^2
hope u got ur answer
heerp:
thanks
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