Question

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(3^p)^3 x 9^2 x 243^-5 = 1
find p​

Answer 1

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Answer 2

${( {3}^{p}) }^{3} \times {9}^{2} \times {243}^{ - 5} = 1 \\ \\ {3}^{3p} \times 81 \times \frac{1}{ {243}^{5} } = 1 \\ \\ {3}^{3p} = \frac{243 \times {243}^{4} }{81} \\ \\ {3}^{3p}=3× ({3}^{ {5})^{4} } \\ \\ {3}^{3p} = 3²¹ \\ \\ 3p = 21 \\ \\ p = 7$