Question

please answer yarr...fast please

Answer 1

use cross multiplication method
like a1= 2,a2= (a-b)x
b1 =3,b2= (a+b)x
c1=-7,c2= -(3a+b-2)

Answer 2

for infinite number of solution


$\frac{a1}{a2} = \frac{b1}{b2} = \frac{c1}{c2} \\ \frac{2}{a - b} = \frac{3}{a + b} = \frac{7}{3a + b - 2}$
$2(a + b) = 3(a - b) \\ - a + 5b = 0$
$3(3a + b - 2) = 7(a + b) \\ 2a - 4b = 6 \\ a - 2b = 3$
add both equations
$3b = 3 \\ b = 1 \\ - a + 5 = 0 \\ a = 5$
so for infinite solution value of a=5,b=1