Question

please answerrrrrrrrrer​

Answer 1

Answer:

answer is 0.365 grams of HCl

Explanation:

AS SAID CACO3 REACTS WITH HCL

CACO3 + HCL GIVES RAISE TO CACL2 + CO2 + H20

BY BALANCING:

CACO3 + 2HCL GIVES RAISE TO CACL2 + CO2 + H2O

BY ADDING THEIR MASS NUMBERS

232g + 37 g GIVES RAISE TO 110g + 44g + 18g

BY THE QUESTION

232g OF CACO3 = 37 g OF HCL

1.5 g of CACO3 = X g OF HCL

BY CROSS MULTIPLYING

X = 37 × 1.5 / 232

BY CALCULATING

X = 0.365 grams of HCL.

HOPE IT HELPED