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Question: A train has a total mass of 7.5 × 10⁵ kg. The train accelerates from rest at a constant rate along a straight horizontal track. It reaches a speed of 24 m/s in 60 s.
Calculate:-
- the train’s acceleration, and
- the resultant force acting on the train.
Solution:-
- Mass of the train = 7.5 × 10⁵ kg
- Initial velocity = 0 m/s (rest)
- Final velocity = 24 m/s
- Time taken = 60 s
We know,
a = (v - u)/t
⟹ a = v/t [since u = 0; v - 0 = v]
⟹ a = (24 m/s)/(60 s)
⟹ a = 0.4 m/s²
NOW, finding resultant force:-
We know,
F = ma
⟹ F = (7.5 × 10⁵ kg)(0.4 m/s²)
⟹ F = 75 × 10³ × 4 N
⟹ F = 300 × 10³ N
⟹ F = 3 × 10⁵ N
@Psyclone
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