Question

which term of the A.P is 7, 10 ,13 ... is 34​

Answer 1

Answer:

a=7 ,

d= t2 -t1 = 10 - 7 = 3

tn = 34

tn = a + (n - 1) x d

34 = 7 + (n - 1) x 3

34 = 7 + 3n - 3

34+3 = 7 + 3n

37 - 7 = 3n

30 = 3n

30/3 = n

10 = n

therefore n = 10

therefore 34 is 10th term of an A.P.

Answer 2

Answer:

n = 10

Step-by-step explanation:

a=7 d=10-7=3 then use formula an =a+(n-1)d 34=7+(n-1)3 ,34-7=(n-1)3 , 27=(n-1)3 , 27/3 = n-1 , 9 = n-1 , n= 9+1= 10