Question

please answers quickly​

Answer 1

it is the right answer for your question.

Answer 2

$\huge\mathfrak\blue{question}$

the base of an isosceles triangel is 4/3 cm . the perimeter is 4 (2/15) cm . Find length of remaining sides.

$\huge\mathfrak\red{Solution}$

$base \: = \frac{4}{3} cm$

$perimeter = 4 \frac{2}{15} cm$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{62}{15}cm$

$\boxed{\pink{Perimeter = 2s + b}} \\ where \: s \: = either \: side \\ b = base$

$\implies 2s + \frac{4}{3} = \frac{62}{15}$

$\implies2s = \frac{62}{15} - \frac{4}{3}$

$\implies2s \: = \frac{62}{15} - \frac{20}{15}$

$\implies2s = \frac{42}{15}$

$\implies \: s = \frac{42}{30}$

$\implies \: s = \frac{7}{5} \: cm$