Question

please answr immediately Pragya tested the solubility of three different substances at different temperatures and collected the data as given below (results are given in the following table, as grams of substance dissolved in 100 grams of water to form a saturated solution).
(a) What mass of potassium nitrate would be needed to produce a saturated solution of potassium nitrate in
50 grams of water at 313 K?
(b) Pragya makes a saturated solution of potassium chloride in water at 353 K and leaves the solution to cool at room temperature. What would she observe as the solution cools? Explain.
(c) What is the effect of change of temperature on the
solubility of a salt?
Temperature in K
283 293 313 333 353
Solubility
Potassium nitrate 21 32 62 106 167
Sodium chloride 36 36 36 37 37
Potassium chloride 35 35 40 46 54
Ammonium chloride 24 37 41 55 66

Answer 1

Answer:

E(a) yes its correct

(b) 37degree c

(c) in k=353

Kclo=32

nacl=37

Kcl=40

Alcl=24.

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Answer 2

(a) At 313 K 62 g of potassium nitrate dissolved in 100 g of water. So to produce a saturated solution of potassium nitrate in 50 g of water we need 10062​×50=31 g of potassium nitrate.

(b)Some soluble potassium chloride will separate out in the form of crystal at room temperature because the solubility of potassium chloride will decrease.

(c)

(i)  Solubility of Potassium nitrate at 293 K is 32 g.

(ii)  Solubility of sodium chloride at 293 K is 36 g.

(iii) Solubility of Potassium chloride at 293 K is 35 g.

(iv) Solubility of Ammonium chloride at 293 K is 37 g.                                                      

The solubility of Ammonium chloride is highest at this temperature.

(d)The solubility of salt increases with the increase in temperature.

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