Question

please anwer send me​

Answer 1

Answer:

As AB is the tangent of length 20cm and radius of circle is 3 cm.

As we know that radius and tangent are perpendicular to each other ,

So,

AOB will be right angle triangle with right angle at A.

ln right angle triangle AOB ab is hypotenuse and AB and AO are perpendicular and base.

So,

$OB = \sqrt{ {20}^{2} + {3}^{2} } \\ = \sqrt{400 + 9} \\ = \sqrt{409}$

So,

length of BC = length of OB + length of OC.

$BC = \sqrt{409} + 3$

As,

Answer is not matched to any option because the question is wrong.

lf the length of tangent is 4 centimetre then the correct option will be came as,

if tangent is 4 cm then

$OB = \sqrt{ {4}^{2} + {3}^{2} } \\ = \sqrt{16 + 9} \\ = \sqrt{25 } \\ = 5cm$

So,

$BC = 5 + 3 = 8cm$