Math, asked by Anonymous, 11 months ago

Please solve 33and 34

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Answers

Answered by siddhartharao77

Answer:

33) 20(2/3)%

34) 13%

Step-by-step explanation:

(33)

Cost of land = 480000

Sold 2/5 land and the amount he got = 480000 * 2/5

= 192000

Loss of 6% percent = 192000(1-6/100)

= 192000(94/100)

= 1920 * 94

= 180480

To gain 10% profit = 480000 * 1.1

= 528000

Selling 3/5 of land = 528000 - 180480

= 347520

Cost of remaining 3/5 land = 480000 * 3/5

= 288000.

Here, Selling price > Cost price. So, gain has occurred.

We know that Gain = Selling price - Cost price

= 347520 - 288000

= 59520.

We know that Gain% = (Gain/CP) * 100

= (59520/288000) * 100

= 20.6667

= 20 (2/3)%.

Therefore, Gain = 20 (2/3)%.

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(34)

Given, Cost price of sugar = 4500.

Cost price of (1/3) of sugar = (1/3) * 4500

= 1500

Gain = 10%.

We know that SP = [(100 + Gain)/100) * CP

= [110/100] * 1500

= 1650

Given, total Gain = 12%.

We know that SP = [(100 + Gain%]/100] * 4500

= [112/100] * 1500

= 5040.

Remaining Cost price = 4500 - 1500

= 3000

Remaining Selling price = 5040 - 1650

= 3390.

Here, Selling price > Cost price.So, Gain has occurred.

Gain = S.P - C.P

= 3390 - 3000

= 390.

Gain% = (Gain/CP) * 100

= (390/3000) * 100

= 13%.

Therefore, Gain = 13%.

Hope it helps!

Answered by Siddharta7