please any body solve this question and show me the solution also. Its urgent
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putting y=mx-m+1 in the equation of circle,
x²+(mx-m+1)²-4x-4(mx-m+1)+4=0
x²(1+m²)+x(-2m²+2m-4-4m)+m²+1-2m+4m-4+4=0
Now just make the D (discriminant) of this equation > 0 so that we have two different values of x, hence giving two points of intersection.
x²+(mx-m+1)²-4x-4(mx-m+1)+4=0
x²(1+m²)+x(-2m²+2m-4-4m)+m²+1-2m+4m-4+4=0
Now just make the D (discriminant) of this equation > 0 so that we have two different values of x, hence giving two points of intersection.
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