Question

Please any exper solve this maths :

Answer 1

Hey mate!

Here's your answer!!

10.
$\sqrt{3 - 2 \sqrt {2} }$
We want : a²-2ab+b² = (a-b)²
3 - 2√2 = (√2)² - 2√2.1 + 1² = (√2 - 1)²
$\sqrt[]{3} - 2 \sqrt{2} = \sqrt{( \sqrt{2} - 1) {}^{2} }$
= √2 - 1.

Do the 9th one by the same method.

Hope it helps you!

Answer 2

Hello Dear!!!

Here's your answer....

Refer the attachment...