Question

please any obe can solve it​

Answer 1

Answer:

D

Step-by-step explanation:

• $\sqrt[n]{A} =A^\frac{1}{n}$
• $A^-^n=\frac{1}{A^n}$.
• $A^xA^y=A^x^+^y$

$\frac{\sqrt{x^3} *\sqrt[3]{x^5} }{\sqrt[5]{x^3} } *\sqrt[30]{x^7^7}$

$=x^\frac{3}{2} *x^\frac{5}{3} *x^\frac{-3}{5} *x^\frac{77}{30}$

$=x^\frac{77}{15}$

(∵$\frac{3}{2} +\frac{5}{3} -\frac{3}{5} +\frac{77}{30} =\frac{77}{15}$)

Answer is (D)

Answer 2

Answer:

D is the correct answer