Question

please any one here solve this question . ​

Answer 1

$\huge\fbox\green{\fbox\pink{Solution:-}}$

$\frac{ {x}^{2} - (x + 2)(x + 3) }{7x + 1} = \frac{2}{3} \\ = > \frac{ {x}^{2} - ( {x}^{2} + (2 + 3)x + 2 \times 3) }{7x + 1}= \frac{2}{3} \\ = > \frac{ {x}^{2} - ( {x}^{2} + 5x + 6) }{7x + 1} = \frac{2}{3} \\ = > \frac{ {x}^{2} - {x}^{2} - 5x - 6 }{7x + 1} = \frac{2}{3} \\ = > \frac{ - 5x - 6}{7x + 1} = \frac{2}{3} \\ = > - 15x - 18 = 14x + 2 \\ = > - 29x = 20 \\ = > x = - \frac{20}{29}$

$\huge\orange{\fbox\blue{Answer:-}}$

$\huge\green{ - \frac{20}{29} }$

$\huge\fbox\green{\fbox\pink{Done \: by \: Aritra \: Kar}}$