Question

please any one solve for me with clear concept.​

Answer 1

Answer:

Hey but i am getting different option which is not in the given answer...

i am getting 1200 ft

i will just recheck it and edit my answer within a while ... but if i dont get it i am really sorry ...

Answer 2

Explanation:

As you can see in figure the angle between the second boat and the horizontal line is 30° (Because the line of helicopter and the horizontal are parallel so by property of alternate angles )

Now let the horizontal distance between boat 2 and helicopter be x

so,

$\tan(30) = \frac{650 - 50}{x}$

$\frac{1}{ \sqrt{3} } = \frac{600}{x}$

$x = 600 \sqrt{3} ft$

Now similarly let horizontal distance between 1st boat and helicopter be y, and again by alternate angles properties angle from horizontal will be 60°

$\tan(60) = \frac{650 - 50}{y}$

$\sqrt{3} = \frac{600}{y}$

$y = \frac{600}{ \sqrt{3} }$

now the distance D will be equal to (x-y)

D=x-y

$= 600 \sqrt{3} - \frac{600}{ \sqrt{3} }$

By cross multiplying

$= \frac{600 \times 3 - 600}{ \sqrt{3} }$

$= \frac{1200}{ \sqrt{3} }$

Now we rationalize the denominator by multiplying and dividing by √3

$= \frac{1200 \sqrt{3} }{3}$

$= 400 \sqrt{3} ft$

So D=400√3 ft

Option (b).