please any one solve using the identity (a+b)(a-b)=a²- b² :
(0.5x)²-(0.2y)²
NobleTriangle:
how did you write that square sign
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Answered by
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(0.5x)²-(0.2y)²=(0.5x+0.2y)(0.5x-0.2y) Hope it helps please mark as branliest
Answered by
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heya here is your answer
(0.5x)^2 - (0.2y)^2
= by using (a+b)(a-b)=a^2 - b^2
(0.5x + 0.2y)(0.5x - 0.2y)
hope it helped u
plz mark as brainliest
(0.5x)^2 - (0.2y)^2
= by using (a+b)(a-b)=a^2 - b^2
(0.5x + 0.2y)(0.5x - 0.2y)
hope it helped u
plz mark as brainliest
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