please anybody send me the solution
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Answered by
1
1.=132/144=11/12
2 probability of one bulb defective =4/20=1/5
Probability after taking out one fine bulb=15/19
2 probability of one bulb defective =4/20=1/5
Probability after taking out one fine bulb=15/19
Answered by
1
8.
the defective pen ==12
good pens ==132
total pens = 132+12 =144
then
the probability of pen good one is = 132/144
= 11/12 answer
9.
TOTAL BULB =20
DEFECTIVE BULB = 4
GOOD BULB = 20-4= 16
THEN
the probabilty of bulb is defective = 4/20
=1/5
now according to question
we select one defective bulb but its not defective
and we cannot count this this bulb again
then
the total bilb = 19
defective = 4
good bulb = 19-4= 15
then
the probability of good bulb = 15/19
HOPE ITS HELP YOU DEAR
the defective pen ==12
good pens ==132
total pens = 132+12 =144
then
the probability of pen good one is = 132/144
= 11/12 answer
9.
TOTAL BULB =20
DEFECTIVE BULB = 4
GOOD BULB = 20-4= 16
THEN
the probabilty of bulb is defective = 4/20
=1/5
now according to question
we select one defective bulb but its not defective
and we cannot count this this bulb again
then
the total bilb = 19
defective = 4
good bulb = 19-4= 15
then
the probability of good bulb = 15/19
HOPE ITS HELP YOU DEAR
anoopsingh2:
welcome now pls add as brainlist
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