Question

Please anybody solve this. My exams are coming.

Answer 1

Answer:

Angle ASD = 30°

angle SDC = 60°

Step-by-step explanation:

ABRS is a rhombus

therefore AB=BR=RS=AS------(1)

(All sides of a rhombus are equal)

Also ABCD is a square

therefore AB=BC=CD=AD-----(2)

(All sides of a square are equal)

Now in triangle ASD,

AS=AD {From (1) and (2)}

therefore angle ASD = angle ADS--(3)

(angles opposite to equal sides are equal in a triangle)

In a triangle,

Sum of all angles=180°

angle ASD + angle ADS + angle SAD = 180°

By(3),

2×angle ASD +120° =180

angle ASD = 30°

ABCD is a square,

angle ADC= 90°

angle ADS+ angle SDC = 90°

angle SDC = 90° - 30° =60°