please anyone answer this question
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Let AB be the tower and ships are at point C and D respectively and CB = x m
CD = 100(✓3+1) / ✓3 m
<CAX = 45° = <ACB
<DAY = 60° = <ADB
tan 45° = AB/CB
=> 1 = AB / x
=> AB = x m
tan 60° = AB / DB
=> ✓3 = x / [(100✓3-100) / ✓3
=> ✓3 = ✓3x / 100(✓3-1)
=> x = 100(✓3-1) m = AB (Height of tower)
CD = 100(✓3+1) / ✓3 m
<CAX = 45° = <ACB
<DAY = 60° = <ADB
tan 45° = AB/CB
=> 1 = AB / x
=> AB = x m
tan 60° = AB / DB
=> ✓3 = x / [(100✓3-100) / ✓3
=> ✓3 = ✓3x / 100(✓3-1)
=> x = 100(✓3-1) m = AB (Height of tower)
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