Science, asked by arindam619, 1 year ago

please anyone explain potential divider bias circuit

Answers

Answered by Ashwinsinghchoudhary
2
hope this will help you

the dc biasing of bipolar junction transistors(BJT) in a simple amplifier circuit. The circuit usually consists of biasing resistors in a voltage divider network whose values are determined through circuit analysis. Utilised in the field of electronic engineering, it forms an important part of small signal analysis for emitter-stabilised circuits.

The dc biasing of BJT is a complicated methodology as there is no single formula to provide the answers. It involves understanding the "Q-Point" and the "DC Load Line", as well as circuit analysis. The following article looks into biasing a simple common-emitter NPN BJT circuit employed within an amplifier.

Why bias a transistor?



A NPN BJT is a component that conducts when there is a positive voltage at the base junction. A positive voltage at the base with respect to the emitter creates a current that flows into the transistor's base junction. The transistor cannot conduct if the voltage at the base is negative because current will not flow into the transistor.

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arindam619: thank you
Ashwinsinghchoudhary: please mark it as a brainlist answer
Answered by brainz6741
3

Answer:

Hii..

Potential or Voltage divider bias:-

Voltage Divider Bias Circuit, also known as emitter current bias, is the most stable of the three basic transistor bias circuits. A voltage divider bias circuit.

It is seen that, as well as the collector resistor (RC), there is an emitter resistor (RE) connected in series with the transistor. As discussed already, the total dc load in series with the transistor is (RC + RE), and this total resistance must be used when drawing the dc load line for the circuit. Resistors R1 and R2 constitute a voltage divider that divides the supply voltage to produce the base bias voltage (VB).

Voltage Divider Bias Circuit are normally designed to have the voltage divider current (I2) very much larger than the transistor base current (IB). In this circumstance, VB is largely unaffected by IB, so VB can be assumed to remain constant.

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