Question

please anyone help me in this question​

Answer 1

Answer:

Solution ⬇️

✍️In ∆ABC and ∆DBC

$= = > given = h1 = 4cm \: .h2 = 6cm$

$= = > \frac{a(angle \: abc) }{a(angle \: dbc)} = \frac{h1}{h2} = \frac{4}{6} = \frac{2}{3} ..triangle \: having \: equal \: time$

$= = > therefore. \frac{a(angle \: abc)}{a(angle \: dbc)} = \frac{2}{3}$

Step-by-step explanation:

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