Math, asked by bhavya807, 1 year ago

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Answered by DevyaniKhushi
1

 {(x - 2y - 3z)}^{2}  \\  {(x)}^{2}  +  {( - 2y)}^{2}  +  {( - 3z)}^{2}  + 2[(x)( - 2y) + ( - 2y)( - 3z) + ( - 3z)(x)] \\  {x}^{2}  +  {4y}^{2}  +  {9z}^{2}  + 2( - 2xy + 6yz - 3xz) \\  {x}^{2}  +  {4y}^{2}  +  {9z}^{2}  - 4xy + 12yz - 6xz

{\text  {\huge{Hence,}}}

[tex{\boxed{ \red{ \boxed{ \blue{ \large{{(x - 2y - 3z)}^{2} = {x}^{2} + {4y}^{2} + {9z}^{2} - 4xy + 12yz - 6xz }}}}}}[/tex]

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