Question

please anyone help me with this. Answer is 5 and 20 cm. Please help me with the solution ​

Answer 1

Answer:

5 and 20 cm

Step-by-step explanation:

Let x = side of one square

Let y = side of the other square

then

4x + 4y = 100

simplify, divide by 4

x + y = 25

y = (25-x), use this for substitution

and

x^2 + y^2 = 425

Substitute (25-x) for y

x^2 + (25-x)^2 = 425 (25-x)(25-x)

x^2 + 625 - 50x + x^2 = 425

Arrange as a quadratic equation

x^2 + x^2 - 50x + 625 - 425 = 0

2x^2 - 50x + 200 = 0

(x-20)(2x-10) = 0

Two solutions

x = 20 is the side of one square

or

2x = 10

x = 5 is the side of one square

Find y

25 - 20 = 5 is the side of the other square

or

25 - 5 = 20 is the side of the other square

anyway, one square side is 20, the other square side is 5

See if this is true

4(20) + 4(5) =

80 + 20 = 100

and

20^2 + 5^2 = 425

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